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5n^2-45n+70=0
a = 5; b = -45; c = +70;
Δ = b2-4ac
Δ = -452-4·5·70
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-25}{2*5}=\frac{20}{10} =2 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+25}{2*5}=\frac{70}{10} =7 $
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